Mathematical Puzzles
Medium
3 min
A rectangle has a perimeter of 50 cm. Its length is 3 cm greater than its width. Find its dimensions.
Hint
Use P = 2(L + W).
Answer
Length = 14 cm and width = 11 cm.
Explanation
L + W = 25 and L = W + 3. Therefore 2W + 3 = 25, giving W = 11 and L = 14.
Step-by-Step Solution
2(L + W) = 50.
L + W = 25.
L = W + 3.
2W + 3 = 25.
W = 11, L = 14.
L + W = 25.
L = W + 3.
2W + 3 = 25.
W = 11, L = 14.